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AB-059 Datasheet

  • AB-059

  • AB-059 - MTTF. FAILRATE. RELIABILITY AND LIFE TESTING

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  • 5頁

  • ETC

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which maximizes the probability of observing what was
actually observed. This is accomplished by taking the partial
derivative of the log
e
of L (偽, t), setting it equal to zero, and
solving for
偽:
r
ln
(L(偽, t))
=
rln (偽) 鈥?/div>
t
i
Now note that
2偽
鈭?/div>
t
i=1
r
i
=
2偽t
1
+
2偽t
2
+...+2偽t
r
鈭?/div>
i=1
i
鈭俵n
(L(偽, t)) r
=
鈥?/div>
鈭偽?/div>
r
鈥?/div>
鈭?/div>
t
i=1
r
As shown, each factor of the above sum is distributed X
2(2)
.
Therefore, by the reproductive property of X
2
the summation
is also distributed X
2
with r times 2 degrees of freedom, X
2
(2r) as stated.
AND FINALLY
The concepts of MTTF, failure rate and reliability have been
defined, discussed and justified. In general, the time units of
device 鈥?hours have been used. With this dimension, failure
rate can be interpreted as the frequency with which failures
can be expected to occur. This description works well with
the experimental estimation of the unknown parameters and
provides an intuitive perspective. However, reliability esti-
mation is, in essence, a probabilistic science and the Weibull
equations are, in essence, probability equations. As a prob-
ability equation, failure rate becomes the probability of
failure per hour, not per device 鈥?hour. The reader is
encouraged to give this distinction some thought.
We perform our life testing at elevated temperatures in order
to accelerate failure mechanisms which might result in
device failure. Our reliability reports generally supply MTTF
estimates scaled over a range of temperatures appropriate to
application environments. The Arehnius equation with an
activation energy selected to represent typical failure mecha-
nisms is employed to generate the tables.
Here at Burr-Brown we use a spreadsheet program to calcu-
late and record the results of life tests. Constant failure rate
is presumed. This presumption should always be verified. It
may not be unreasonable to interpret MTTF as the mean
time to the first failure even if the failure rate is not constant.
However, failure rate and reliability predictions based on
that MTTF will be wrong.
APPENDIX A
dexp (鈥撐眡
) / dx
=
exp (鈥撐眡
) d(鈥撐眡
) / dx
鈭?/div>
t
i
=1
r
r
i
=
0
using
to indicate the approximation,
1
=
鈭?/div>
t
i
=1
i
r
This equation shows that 1/偽 can be estimated by dividing
the accumulated test time for all of the tested devices by the
total number of failures. This agrees with the original defi-
nition of MTTF.
Understanding the chi-square, X
2
, confidence interval calcu-
lation requires recognition that given the random variable
for time-to-failure, T, has distribution
f (t)
= 偽e
鈥?/div>
偽t
then the random variable V described by
V
=
2偽
鈭?/div>
t
i=1
r
i
is distributed X
2
with 2r degrees of freedom, X
2
(2r). There-
fore, for a specified confidence level 莽
2偽
鈭?/div>
t
i=1
r
i
>
X
2
(2r,味)
and the upper confidence limit for MTTF becomes
2 t
i
1
i=1
<
=
MTTF
偽 蠂
2
(2r,味)
鈭?/div>
r
=
exp (鈥撐眡
) (鈥撐蔽? (x
尾鈥?
)
=
鈥?/div>
偽尾x
尾鈥?
exp (鈥撐眡
)
therefore replacing
鈥?/div>
which, with r equal to the number of observed failures + 1,
is the actual formula we use for MTTF.
To justify the X distribution of the random variable V used
above, apply the transformation of variable
2
鈭?/div>
t
0
偽尾x
鈥?
exp (鈥撐眡
) dx
=
鈥?/div>
V
/
=
2偽T,
to f(t) which results in
f (v)
= 偽e
2
dT
1
/
=
dV
2偽
V
鈭?/div>
d exp (鈥撐眡 ) / dx dx
=
鈥?/div>
鈭?/div>
d exp (鈥撐眡 )
0
t
t
0
and
R(t)
=
1
+
鈭?/div>
d exp (鈥撐眡
0
t
0
t
)
鈥撐?/div>
V
2偽
1
1
鈥?/div>
=
e
2
2偽 2
=
1
+
exp(鈥撐眡
) |
2(2)
which is distributed X with 2 degrees of freedom, X
Appendix B).
(see
4
=
1
+
exp(鈥撐眛
) 鈥?1

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