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LT1533C Datasheet

  • LT1533C

  • Linear Technology [Ultralow Noise 1A Switching Regulator]

  • LINER

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LT1533
APPLICATIONS INFORMATION
For continuous operation the inductor ripple current must
be less than twice the output current. The worst case for
this is at maximum input (lowest DC) but we will evaluate
at nominal input since the I
OUT
/4 is somewhat arbitrary.
Note when both inputs are off, inductor current splits
between outputs and the diode common goes to 0V.
Looking at the inductor current during off time, output
ripple current is:
鈭咺
OUT
= 2 鈥?I
OUT(MIN)
I
OUT(MIN)
= I
OUT(MAX)
/4
and the peak current in the switch is:
I
SW(PEAK)
= N 鈥?I
LMAX
+
鈭咺
MAG
This should be less than the 1A current limit.
In the push-pull converter the maximum switch voltage
will be 2 鈥?(V
IN
鈥?V
SW
) plus a small amount (10%) for
leakage spikes. Because voltage is slew-controlled, the
spikes will be less than normal. So, maximum switch
voltage is:
V
SW(MAX)
= 2 鈥?V
IN
鈥?1.1
This should be below the maximum rated switch voltage.
So, given the turns ratio, primary inductance and current,
the transformer can be designed. As an example:
V
IN
= 5V
鹵10%,
V
OUT
= 12V, I
OUT(MAX)
= 150mA,
V
SW
= 0.5V, V
F
= 0.5V, f = 50kHz,
N
=
L
O
=
V
OUT
1
鈭?/div>
2
鈥?/div>
DC
NOM
鈭?/div>
I
OUT
鈥?/div>
f
(
)
The inductance of the transformer primary should be such
that L
O
, when reflected into the primary, dominates the
input current. In other words, we want the magnetizing
current of the transformer small with respect to the
current going through the transformer to L
O
. In general,
then, the inductance of the primary should be at least five
times that of L
O
. This ensures that most of the power will
be passed through the transformer to the load. It also
increases the power capability of the converter and
reduces the peak currents that the switch will see.
L
PRI
= 5 鈥?L
O
/N
2
If the magnetizing current is below 100mA, then a smaller
L
O
can be used.
With the value of L
O
set, the ripple in the inductor is:
鈭咺
OUT
=
V
OUT
1
鈭?/div>
2
鈥?/div>
DC
L
O
鈥?/div>
f
(
)
However, the peak inductor current is evaluated at maxi-
mum load and maximum input voltage (minimum DC).
I
LMAX
=
I
OUT
(
MAX
)
+
鈭?/div>
I
OUT
(
MAX
)
2
The magnetizing ripple current can be shown to be:
V
+
V
鈭咺
MAG
=
OUT F
N
鈥?/div>
L
PRI
鈥?/div>
f
12
U
W
U
U
(
2
鈥?/div>
0
.
44
)(
4
.
5
鈭?/div>
0
.
5
)
12
+
0
.
5
=
3
.
55
Round up so N = 3.6.
For continuous operation at I
OUT(MIN)
= I
OUT(MAX)
/4,
inductor ripple is:
鈭咺
OUT
=
2
鈥?/div>
150mA
=
75mA
4
The duty cycle for nominal input is:
DC
NOM
=
=
(
2
鈥?/div>
3
.
6
)(
5
鈭?/div>
0
.
5
)
12
(
1
鈭?/div>
2
鈥?/div>
38
.
6
%
)
=
730
碌
H
L
O
(
MIN
)
=
75mA
鈥?/div>
50kHz
12
+
0
.
5
(
2
鈥?/div>
N
)(
V
IN
(
NOM
)
鈭?/div>
V
SW
)
=
38
.
6
%
V
OUT
+
V
F
Off-the-shelf components can be used for this inductor.
Say we found an 800碌H inductor (Coiltronics CTX200-1
for instance).

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